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Questions and answers by
Sani mohammed
Answers (1)
A)distance qr= |ar|^2=q^2+r^2-2pqcosP =90^2+50^2-2*50*90cos125 =8100+2500-9000cos125 =10600+5162.1879 =root of 10600+5162.1879 qr=130 b)The bearing of r from q= =q/sinQ=p/sinP =90/sinQ=130/sin125 =130sinQ=90sin125 Q(sin)=73.72/130 Q=34.6 Then the bearing
