Sandeep Kumar
This page lists questions and answers that were posted by visitors named Sandeep Kumar.
Questions
The following questions were asked by visitors named Sandeep Kumar.
How to find stationary points for this function: f = [6x (cosy)-2(x^2)(cosy)+(x^2)(sin2y)]
5 years ago
Could anyone, please, help me solve this? Let f be a function with the domain the set of all real numbers except 0 and 1 ,that satifies the equation : 2xf(x) - f[(x-1)/x] = 20 Find f(5/4)
5 years ago
Find the range of all possible values of B if the graph of P(x) = 12x⁴ - 5x³ -38x² + Bx + 6 crosses the x-axis between 0 and -1
5 years ago
Answers
The following answers were posted by visitors named Sandeep Kumar.
21 years
6 years ago
(45+x)=2(12+x).
6 years ago
I have almost solved this problem now. I'm still wondering what is meant by "single stationary point within range"? In actual problem, it was asked to find single stationary point in range 0<x<6 and the corresponding value of y. But after solving equation...
5 years ago
-8f(-4)-f(5/4)=20 or f(5/4)= -8f(-4)-20 Now what to do with f(-4)? How to find it?
5 years ago
Given: Total mass (M) = 800 kg Tension in the cable (T) = 9300 kg ms⁻² Mass of Man (m) = 80 kg * Then equilibrium of forces in vertical direction will be: T-Mg=Ma Where, g= acceleration due to gravity and a= acceleration due to upward force(acceleration o...
5 years ago
Population t years after 1980 is given by: 𝒹ₚ/𝒹ₜ = N(t) = 213 e⁰·⁰¹⁰¹ ᵗ integrating it we get, P= 213·C·e⁰·⁰¹⁰¹ ᵗ ...(i) [Where C is a constant of integration] when t=0 i.e. in 1980, P= 213C when population of 1980 is doubled, i.e P= 2P= 2×213·C Now from...
5 years ago
Actually I didn't read it thoroughly and quickly replied you. Then I left the site and kept trying to solve it. I got the answers. Now I just came back and saw your replies, which is exactly the same method. Thank you for your help.
5 years ago
Actually this was all to explain the person who posted the problem. I could have skipped some lines. I don't know what his/her level of education is, so I just used my own method to solve it and also explained it well enough to be understood. Thank you fo...
5 years ago
Could you explain what you did in the first and the last line of your comment?
5 years ago