Sai prasanna

This page lists questions and answers that were posted by visitors named Sai prasanna.

Questions

The following questions were asked by visitors named Sai prasanna.

Answers

The following answers were posted by visitors named Sai prasanna.

Radius of 1 circle = x,radius of2 circle=14-x. Now,area of circle = piR2. So,pi(x2)+pi(14-x)2=130pi. Pi(x2+196-28x+x2)=130pi. Pi at both sides is cancelled So 2x2-28x+196-130=0. 2(x2-14x+33)=0. X2-11x-3x+33=0. X(x-11)-3(x-11)=0. So, x= 3,11
9 years ago