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if the degree of dissociation of one molar monoprotic acid is 10 percent. calculate its Ka value?
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moles of CaCO3=0.02 by comparing moles of HCl=0.04 mass of Hcl=0.04*36.5=1.46g we know that the molarity of Hcl solution is 2 and its percentage 7 SO 7g of HCl present in Hcl solution=100g 1g of HCl present in Hcl solution=100/7 1.46g of Hcl present in HCl