SAGAR BASNET

This page lists questions and answers that were posted by visitors named SAGAR BASNET.

Questions

The following questions were asked by visitors named SAGAR BASNET.

Answers

The following answers were posted by visitors named SAGAR BASNET.

FROM L.H.S I SOLVE INDIVIDUALLY AND COMBINE FOR CONVIENIENCE Solving (3-4 sin^2a) (3-4 sin^2a) = 3-3 sin^2a-sin^2a= 3 cos^2a-sin^2a Now,solving (1- 3 tan^2 a) (1- 3 tan^2 a)= 1- 3sin^2 a/cos^2 a=(cos^2a - 3 sin^2 a) /cos^2 a putting both solved answer , w...