Ask a New Question
Search
Questions and answers by
SAGAR BASNET
Answers (1)
FROM L.H.S I SOLVE INDIVIDUALLY AND COMBINE FOR CONVIENIENCE Solving (3-4 sin^2a) (3-4 sin^2a) = 3-3 sin^2a-sin^2a= 3 cos^2a-sin^2a Now,solving (1- 3 tan^2 a) (1- 3 tan^2 a)= 1- 3sin^2 a/cos^2 a=(cos^2a - 3 sin^2 a) /cos^2 a putting both solved answer , we
