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mols of HCl= 0.1N X 0.5L=0.05 mols of HCl
Therefore, number of mols of 2N NaOH needed to obtain pH 6.8: 0.05 mols HCL/2 = 25 mL
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How much sodium hydroxide, at what concentration, do I need to add to 500 mL of 0.1 N HCL to obtain pH 6.8. How do you calculate
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2.0kg block of iron transfers 180,000j to the atmosphere around it. If its initial temperature was 350 celius what is it's final
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