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Questions and answers by
Rounak Bhandari From Nepal Bhairahawa
Answers (1)
L.H.S= (3-4sin^2A)(1-3tan^2A) (3-4sin^2A)(1-3sin^2/cos^2A) (3-4sin^2A)(cos^2A-3sin^2A)/cos^2A (3-4sin^2A)/cos^2A(cos^2A-3sin^2A) (3sec^2A-4tan^2A)(cos^2A-3sin^2A) (3sec^2A-4tan^2A)(cos^2A-3+3cos^2A) (3+3tan^2A-4tan^2A)(4cos^2A-3) (3-tan^2A)(4cos^2A-3)
