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Questions and answers by
Rohit vishwakarma
Answers (1)
Amount of ammonia initially = 0.050 x 0.0240 =0.0012 mol. Amount of HCl added =0.015 x 0.0600 = 0.0009 mol. Amount of ammonia left = 0.0012-0.0009 =0.0003 mol. Amount of NH4+ ion = Amount of HCl added = 0.0009 mol. pOH= pKb + log(NH4+/NH3) pOH= -log(1.8 x
