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Roger the Mole

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(19.9 g) / (31.4 g) = 0.634 = 63.4% yield
A. (0.800g BaCl2) / (208.233g BaCl2/mol) = 0.00384 mol BaCl2 B. (0.940 g - 0.800 g) / (18.01532 g H2O/mol) = 0.00777 mol H2O

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