Roger the Mole

This page lists questions and answers that were posted by visitors named Roger the Mole.

Questions

The following questions were asked by visitors named Roger the Mole.

Answers

The following answers were posted by visitors named Roger the Mole.

A. (0.800g BaCl2) / (208.233g BaCl2/mol) = 0.00384 mol BaCl2 B. (0.940 g - 0.800 g) / (18.01532 g H2O/mol) = 0.00777 mol H2O

(19.9 g) / (31.4 g) = 0.634 = 63.4% yield