RocknRoll

1) (lambda*exp(-lambda*t) - lambda*exp(-lambda)) / (1-(lambda+1)*exp(-lambda)) 2) 2*(1-t) Both can be obtained using Bayes' rule P(A|B) = P(A)P(B|A) / P(B). I cannot say for sure they are right, but as a first test their integral from 0 to 1 (domain for t...

Agree with mean = 450 As the variance is concerned: we CAN'T consider 30*Xi and so 30^2*var(Xi) because it does not make sense to multiply by 30 the 'randomness' of a single day. Actually, is it more appropriate to think at X as x1+x2+...+x30. Given that...