Ask a New Question
Search
Questions and answers by
Robina
Questions (1)
f(x) = 0 if x<-3
f(x) = 4 if -3≤x<1 f(x) = -2 if 1≤x<5 f(x) = 0 if x≥5 g(x) = integral from -3 to x of f(t)dt g(-4) = 0
1 answer
454 views
Answers (2)
Nevermind, I found it myself by drawing the graph and doing rectangles. g(2) = 14 g(6) = 8 x=1 with max area of 16
f(29) = f(1) + integral [1, 6] f'(x)dx = 15 + 29 = 44.
