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Retaj
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[ HB] eq = [HB ] initial = 2.65M pOH= 14-pH = 14 - 12.54 = 1.46 OH- = 10^-pOH = 10^-1.46 = 0.035 Kb = [B-][OH-] / [HB] Assume [B]=[OH-] (weak base) Kb = [OH-]^2 / [HB] Kb= [0.035]^2 / [2.65] Kb= 4.6 * 10^-4
hi please help me with math.
