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d=m/v v=225mL=225cm³ d(water)=1g/cm³ m=225g Q=mcΔT Q=225 × 4200×(47.8 –20) Q=225 × 4.2 × 27.8 Q=–26271j/mol Q=–26.271kj/mol 2mole ==> –26.271kj/mol 1mole==> xkj/mol x=–13.1355kj/mol
