Answers by visitors named: Rajkumar

Let the North be represented by Y axis.  The when the car turns left, it moves along the -ve x axis, towards West. Let Change in velocity is = \vec{v2}-\vec{v1}=-50\hat{i}-50\hat{j}\ kmph Magnitude of change in velocity=sqrt{50^2+50^2}=50\sqrt{2} Direction of the change in velocity = South west , 45 deg. from South towards West.

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