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pH=-log((H^+)) Log((H^+))= -pH (H+)=10^-pH Now we substitute in the value of the pH given and calculate the hydrogen ion concentration: (H^+)=10^-14.10 (H+)=7.9×10^-5= H+=7.9×10^-5 mol/L Because of the logarithmic scale the value of the pH has two