RESPONSE

This page lists questions and answers that were posted by visitors named RESPONSE.

Questions

The following questions were asked by visitors named RESPONSE.

Answers

The following answers were posted by visitors named RESPONSE.

Thanks i got to read that post... but now that I got to this I don't see what is wrong with doing it this way but i guess it is important to solve both ways heres what I did -4cos^2 x + 2cosx + 2 =0 factored (-4cosx - 2)(cosx - 1) = 0 -4cosx - 2 = 0 or co...

hmmm how did you go from this a(log3+logn)=b(log4+logn) to this? logn(a-b)=blog4-alog3 logn=( )/(a-b)

well if follow now but don't know how to take the anti log of that mumbo jumbo n = 10^(3((blog4-alog3)/(a-b) ) im unsure how that simplifies