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RD Statistics
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n = 18 xbar = 2.56 s = 0.05 H0 : mu = 2.52 H1: mu not equal 2.52 test stat = t = (xbar-mu)/(s/sqrt(n)) = 3.39 p-value = 0.003 < 0.05 Reject H0 t-critical = 2.11 < 3.39 Reject H0 CI =(xbar-t-critical*s/sqrt(n), xbar+t-critical*s/sqrt(n)) (2.54, 2.58)
Independent
F ratio = (30/2)/(60/15) = 15/4 = 3.75
F(0.05, 2, 12) = 3.88.
The critical value of F1 = F (0.05, 2, 15) = 3.68 and F2 =F (0.01, 2, 15) = 6.35. As F = 4.10 > F1 but < F2, Reject the null hypothesis with á = .05 but not with á = .01. (a) is the correct choice.
d. 3 treatments and 39 subjects. first df 2 = t-1 so t = 3 and second df = 36 = N- t => N = 36 + 3 = 39.
X P(X) x*P(X) x^2*P(X) 5 0.6 3 15 2 0.3 0.6 1.2 1 0.1 0.1 0.1 Mean = sum x*P(X)=3.7 sum (x^2 * P(X)) = 16.3 Variance = (x^2 * P(X)) - Mean^2 =16.3 - (3.7)^2 = 2.61 Mean = 3.7 miles and variance = 2.61 miles square
P(Person has blue eyes) = 35/100 = 0.35. P(Randomly selected person does not have bluw eye) = 1- 0.35 = 0.65.
