RAJU BANERJEE

This page lists questions and answers that were posted by visitors named RAJU BANERJEE.

Questions

The following questions were asked by visitors named RAJU BANERJEE.

Answers

The following answers were posted by visitors named RAJU BANERJEE.

Ï€r^2=2Ã—28/11 r=14/11 let,a=Ï€r^2 da/dt=2Ï€r dr/dt 2 =2Ï€Ã—14/11Ã—dr/dt dr/dt=11/14Ï€ =1/4 =.25

πr^2=2×28/11=56/11,r=14/11 Now a=πr^2 And derivative w.r.t t,we get da/dt=2πr dr/dt 2=2π×14/11×dr/dt dr/dt=11/14π=1/4=.25