Q1

A car acceleration from rest 45 m\s in 15 s average acceleration is.....

1. Given that known variable k = 338 N/m and F=mg=6.2(9.8), we will use Hooke's Law(F=-kx) to calculate the stretched distance for the spring. F=mg=-kx which is 60.76=338x. Therefore, x = 0.18m