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A force of 2 N stretches a hookian spring by 2 cm of its original length. What force Will further stretch it by 3 cm

Please help me. A spring with a length of 30 cm is stretched to 36 cm by a mass of 0.1 kg attached to its lower end. The length is further stretched to a length of 40 cm by a certain mass . Determine the mass and state the law used.

(x+7.5)/3.8=x/0.95 3.8x=0.95(x+7.5) 3.8x=0.95x+7.125 3.8x-0.95x=7.125 2.85x=7.125 285x/100=7125/1000 x=7125*2850 x=2.5

Please help me I can't get to the right answer