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Praket Tiwaskar
Answers (1)
Question: log3 243 - log2 64 + log√3 3 This can also be written as: log3 3^5 - log2 2^6 + log√3 √3^2 = 5log3 3 - 6log2 2 + 2log√3 √3 [Since loge m^n = nloge m] = 5(1) - 6(1) + 2(1) [Since logm m = 1] = 5-6+2 = 1
