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Prakash
Questions (8)
Which formula is used to find the length of perpendicular from origin to the line x/a + y/b = 1?
3 answers
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if x be the A.M between y and z,y be the G.M between z and x then x y z are in
1 answer
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What is the probability of occuring 54 tuesdays in leap year?
3 answers
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Find the depth of a pond if its radius is 1.5m and the amount of water it can hold it can hold is 755.6
1 answer
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Three coins are tossed simultaneously ,find the probability of getting at least2 heads
3 answers
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A women is 6 years younger to her husband and he is 5 times as old as his daughter. If daughter was 7 years old 2 years back,
1 answer
214 views
ABC is a triangle.P,Q and R ARE THE MIDPOINTS OF BC , AC AND AB RESPECTIVELY.L IS ANY POINT ON BC DRAWN THROUGH VERTEX A.
PROVE
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A 90% confidence interval for a population mean based on 144 observations is computed to be (2.7,3.4). How many observations
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Answers (7)
Find the depth of a pond if its radius is 1.5m and the amount of water it can hold is 755.6 liters.
Hi Carol, No one will be able to solve this one. haha.
Use simultaneous equation method: x=-y-z-1...(1) Now, the equation 2 become: 2(-y-z-1)+2y+5z=1 -2y-2z-2+2y+5z=1 3z=1+2; z=3 Now equation 1 becomes x=-y-3-1=-y-4; i.e, x=-y-4....(a) equation 3 becomes: 5(-y-4)+2y+3(3)=8 -5y-20+2y+9=8 -3y=19; y=-19/3 Now the
By taking the natural logarithm of both sides: 2^(2x + 11) = 3^(x - 2) ==> ln[2^(2x + 11)] = ln[3^(x - 2)] ==> (2x + 11)ln(2) = (x - 2)ln(3), since ln(a^b) = b*ln(a) ==> 2x*ln(2) + 11ln(2) = x*ln(3) - 2ln(3), by distributing ==> 2x*ln(2) - x*ln(3) =
y=f(x)= x^2-19x+x-19+7= x^2-18x-12 Find the critical value: f'(x)= 2x-18, set it equal to zero 0= 2x-18 hence, x=9 is the critical value Find the second derivative: f"(x)= 2 & f"(9)= 2, since the second derivative is positive, the function has a minimum at
First factor out 3 x^2(common terms) 3x^2 (2x^4-5x+7)
By definition of Limit : The left limit value should be equal to right limit value . lim f(x) = lim f(x) = lim f(x) x->a- x->a+ x->a In our problem say The left limit values lies between 0 to 2 lim ln 2x = lim 2 ln x x->2- x->2+ ==> ln 4 = 2 ln 2 [Hint ln
