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Potassium

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2-methylbutan-1-ol is oxidised by potassium dichromate:2-methylbutan-1-ol + [O] ==> 2-methylbutan-1-al + water
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a) In a reaction, 2-methylbutan-1-ol is oxidised by potassium dichromate. Write equations for the two oxidation steps of this
1. 4 answers
2. 217 views

The displayed formula and structural formula are similar. The question asked for a displayed formula. Every bond has to be shown as an individual line in a displayed formula. Yes, I am not equipped with the tools to draw water with a bond angle of 105. I
How do I draw the displayed formula of water? Option 1: H - O - H Option 2: O / \ H H Are both the displayed formula? Which one do I draw?
Is this 2-methylbutan-1-al? -----H--H-CH3---O ----- I---I----I-----// H - C - C - C- C ------I----I---I-----\ -----H---H--H-----H
-----H--H---H -----O ------I---I----I -----// H - C - C - C - C -----I----I----I -----\ -----H--H-CH3 ---OH 2-methylbutanoic acid Is this correct?
Also, COOH equations look like below at the COOH part: --------O -------// H - C -------\ --------OH Methanoic acid I drew 2-methylbutanoic acid below differently: -----H--H---H ------I---I----I H - C - C - C - COOH -----I----I----I -----H--H-CH3 Can the
1) ----H--H--CH3--H -----I----I----I----I --------------------------------------------------- how do I draw the H - C - C - C - C - O - H -- + how do I draw the [O] ==> 2-methylbutan-1-al -----I-----I----I----I
Draw (as displayed formula) the two products of this reaction.

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