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The following questions were asked by visitors named Please Check!.

4. Use the information above to write net ionic equations for the two reactions that you have observed. 5. For each reaction, write the two half-reactions that make it up and calculate the overall reaction potential by adding the two half-reactions. Each...
13 years ago

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The following answers were posted by visitors named Please Check!.

Sn2+ (aq) + 2Hg2+ (aq) + 2Cl (aq)--> Sn4+ (aq) + Hg2Cl2 (s) Hg2Cl2 (s) + Sn2+ (aq) --> 2Hg (I) + Sn4+ (aq) + 2Cl- (aq) 5. Sn(2+) --> Sn(4+) + 2e- Eo = -0.15 V 2e+ + 2Hg(2+) + 2Cl --> Hg2Cl2 Eo = 0.85 V Total: 0.75 V Hg2Cl2 + 2e- --> 2Hg(2+) + 2Cl- Eo= 0.2...
13 years ago
Those are different from the original post, I am trying to work on it!
13 years ago
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