Physics PLEASE

You want to show that V^2 - Vo^2 = 2 a (X - Xo) first rewrite that as: (V-Vo)(V+Vo) = 2a (X-Xo) now your average velocity during the interval = (V+Vo)/2 so X = Xo + t(V+Vo)/2 but V = Vo + a t so t = (V-Vo)/a so X = Xo +(V-Vo)(V+Vo)/2a we are there. ------...

Of course you have to rearrange it X -Xo = (V-Vo)(V+Vo)/2a (X-Xo)2a = (V-Vo)(V+Vo) 2 a (X-Xo) = V^2-Vo^2 ok to go from the first line to the second line you multiply by 2a I agree but what allows you to just put parenthsess around the X-Xo Thank You!

I'm trying to solve this problem Calculate (a) how long it took King Kong to fall straight down form the top of the Empire State Building (380 m high), and (b) his velocity just before "landing". My teacher said try and rearagne this equation for t X = Xo...

This is what i did x = 2^-1(v0 + v)a^-1(v-v0) + x0 simplfy x = (a2)^-1(v^2 -v0^2)+ x0 (x = (a2)^-1(v^2 -v0^2)+ x0)2a (2a)x = (v^2-v0^2) + x0 (2a)x - x0 = (v^2-v0^2) + x0 - x0 (2a)x - x0 + v0^2= (v^2 - v0^2) + v0^2 (2a)x - x0 + v0^2 = v^2 i do not see were...

thanks

oh... Xo is not zero