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Phu DV
Answers (1)
The solution of 30% (w/w) NH3, i.e. 30 g NH3 + 70 g H2O = 100 g. with d = 0.982 g/ml -> 100 g solution = 101.8 ml; and molality = 30 g (NH3)/17 (g/mol) = 1.76 mol of NH3 in 100 g (or 101.8 ml) solution; So Cm = 1.76 (mol)*1000 (ml)/101.8 (ml) = 17.3 mol/L
