Philip Almeria

This page lists questions and answers that were posted by visitors named Philip Almeria.

Questions

The following questions were asked by visitors named Philip Almeria.

Answers

The following answers were posted by visitors named Philip Almeria.

F= 270 2 +300 2 +2(270)(300)cos60 ​ =494 N \theta=\arctan{\frac{(300)\sin{60}}{270+(300)\cos{60}}}=31.7\degreeθ=arctan 270+(300)cos60 (300)sin60 ​ =31.7°
3 years ago