Pd

f(x)=-x^3+3x^2+9x-5 asked to find the stationary points this was my working and i don't know if it is correct f dash of x = -3x^2+3(2x)+9 -3x^2+6x+9 at local max and min f(x) should =0 -3x^2+6x+9=0 3x^2-6x+9 x^2-2x+3=0 stationary points would be at (x+3)...

i asked about stationary points which came out at (x-3) and (x+1) i am now trying to use the first derivative test to classify the left hand point... (x-3) so picking an xL point of -4 and an xR point of -1 i get this f ' (-4) = 3 16 - 4 + 9 = 48 - 24 + 9...

find any stationary points of the function g(x) = (2x-3)square root of 5+16x-4x^2 (0 less than or equal to x less than or equal to 4) and use the first derivative test to classify each stationary point as a local maximum or local minimum of g(x) this is h...