Ask a New Question
Search
Questions and answers by
Pannag
Answers (1)
m=1362kg,v=22.22m/s,d=61m; we know that a moving object has a kinetic energy=1/2mv^2.So the braking action would be the negative of the work done against Kinetic energy, W(braking)=-K.E i.e 0.5*1362*22.2*22.2, we get,W=-335624.04. now,F=W/stopping dist.
