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A) 8*7*6*5*4*3*2*1 Let's say that the first set is {a,b,c,d,e,f,g,h} and the second set is {1,2,3,4,5,6,7,8}. a can be grouped in 8 different ways, afterwards, if you've already grouped a then that leaves b with 7 elements to choose from and then c with 6
