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Oria noor
Answers (1)
pH = pKA + log salt/acid 4.80 = 4.74 + log salt/acid 4.80-4.74= log salt/acid 0.06 = log salt/acid antilog0.06 = salt/acid 1.148 = salt/acid total=1.148+1=2.148 salt=1.148*0.15/2.148 =0.080moles acid = 1*0.15/2.148 = 0.0698moles
