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Questions and answers by
Omkar Tikekar
Answers (1)
Let the body 0.98 m above be B and the lower body be B*. THEREFORE:- for B u= 0m/s g=(-9.8)m/s² ( - sign because of sign convention) t=2 s So By - S= ut+½at² S=½(-9.8)(4) S= -19.6 m.-------1) For second body B* u=0 a=-9.8m/s² t=2 s S*=ut+½at²
