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OldChemistryBeak
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This puzzled me for a while. But find the mass of 1 mole of HgS [232.67g/mol] Mass of 1 HgS unit is 232.67/6.023 x 10^23 = 3.863 x 10^-22 g [divide mass of 1 mole by Avogadro number] If solubility is 3 x 10^-25 g/L then solubility = mass/volume so 3 x
