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Ogbemudia Omega joy
Answers (1)
Volume of the right circular cone= 1/3pi *r^2×h = 5 pi x r^2 ×h = 15 : r=1/3, h= 1/3 The volume of the cone = 1/3 × pi ×(1/3r) 2×1/3h = 1/3 pi x1/9r^2x1/3h From eqn 1 Pi x r^2 x h = 15 1/81× 15 = 0.185 or 185ml. Volume of frustum = 5 - 0.185= 4.815ml
