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OUATTARA MAMANDOU
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Good job Mr Ouattara. Your answers are just excellent. You are brillant.
OUATTARA MAMANDOU CCNY-CUNY EXO: 7.47 page 281 P=0.75 Q=1-0.75 = 0.25 N=200 A- SE(^P)=sqrt (P.Q)/N where Q=1-P SE(^P)=sqrt(0.75*0.25)/200 =0.306 SE(^P)=0.0306 Approximately normal with mean of 0.75 and standard deviation of 0.0306 B- Let find the Zscore of