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Nsiah Reynold
Answers (2)
This is an arithmetic progression a=800 d=600 From 1985 to 2012 would be the 28th term: =a+27d 8000 +27(600)=24200 He would receive 24200 in 2012
A). For the first 8 yrs a=6400 d=240 beginning the 9th year(I.e) after the 8th year a=9500 d=360 So 7years more to his 15th salary (I.e 15-8=7) Thus 7th term from the 8th year A_7=a+6d =9500+6(360) =11660(his 15th salary) B. Sum of the 1st 8 terms plus sum
