Novindra

first get the KE of the bullet KE = ½mV² = ½(0.003)(240)² = 86.4J heat of fusion of ice is 334 kJ/kg set the KE from above to melting ice 86.4J = 334000 J/kg x M solve for M M = 0.0002587 kg of ice (d) sorry, I use metric (SI) system only, which does not...