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For 74A52B1, Divisible by 3, 7+4+A+5+2+B+1=19+A+B……………[1] For 326AB4C, Divisible by 3, 3+2+6+A+B+4+C=15+A+B+C………[2] A+B=-19…………[1] A+B=-C-15………[2] So, C+15=19 C=19-15 C=4

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