Niranjan

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Questions

The following questions were asked by visitors named Niranjan.

Q.4. Calculate the binding energy per nucleon of 20 Ca40 which has atomic mass of 39.975 a.m.u The mass of hydrogen atom is 1.0078 a.m.u and that of neutron is 1.0086 a.m.u (1 a.m.u = 931 Mev) (10)

The sum of first four terms is a G.P. is 30 and that of the last four terms is 960. Is its term is 2, find the common ratio.

lim x approaches 64 6th root of only x and -2/ cube root of only x and -4

Answers

The following answers were posted by visitors named Niranjan.

The question asks us to make groups with AT LEAST 4 students in each. So, 3 groups with 8 in each also works. And 2 groups with 12 in each works. Pay attention to detail.