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Nicolai
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Calculate the mass of solid Na2S2O3•5H2O required to prepare 300. mL of 0.0200 M Na2S2O3
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ok.. that's what I had done before.. Na2s203 has a mass of 158.11g so I get for 0.006 mol of Na2s203 = 0.9486 g or with 3 significant figures = 9.48 mg. but this still comes up as wrong when I put it into my online portal for my lab.
