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Two facts: A freely falling object at Earth’s surface drops vertically 5 m in 1 s. Earth’s curvature “drops” 5 m for
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Two colliding objects exert equal and opposite forces on each other (Newton's Third Law). However, acceleration experienced by
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I am so confused. What are the real answers. Just in case there are diffferent test , here is the first question for mine. 1. For the data in the table, does y vary directly with x? If it does, write an equation for the direct variation. X Y 8 | 13 16 | 26
both take the same amount of time, t distance of tourist from car d = 3.8 t distance of bear from car = 3.8 t + 27 = 6 t so 2.2 t = 27 t = 270/22= about 12.3 seconds d = 3.8 t = 3.8 * 270/22 = 46.6 m max

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