Nayyab

Suppose that f(x) is bounded: that is, there exists a constant M such that abs(f(x)) is < or equal to M for all x. Use the squeeze theorem to prove that lime x^2f(x)=0 as x approaches 0.

find all discontinunities and remove if possible: F(x)= 2x if x<_0 sin x if 0<x<_pi x-pi if x>pi i cannot find any discontinunities, i keep getting that the function is continuos.

find all discontinunities and remove if possible. f(x)= (4x)/(x^2+x-2) i found discontinunity at x=1 and x=-2 but i don't think they are removable bc they are vertical asymptotes and just wanted to make sure. Thanks.

if g(x) is Mx^2 then what is f(x) and h(x) according to the squeeze theorem.