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4Al +3O2-------------> 2Al2O3 4Al----------->2Al2O3 1Al---------> 2/4 Al2O4 First convert grams to moles Moles of aluminum = 13.5/27 =0.5 Now we have moles 0.5 moles of Al = 0.5 ×2/ 4 = 1/4 So we have moles of Al2O3 now but in question they asked us in
4Al +3O2-------------> 2Al2O3 4Al----------->2Al2O3 1Al---------> 2/4 Al2O4 First convert grams to moles Moles of aluminum = 13.5/27 =0.5 Now we have moles 0.5 moles of Al = 0.5 ×2/ 4 = p
