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Nashwa
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NO3^- + I^- > IO3^- +NO2 N (on the reactant) oxidation# is 5 (on the product) oxidation# is 4 there will be 1 mole of e- on the oxidation 1/2 reaction I (on the reactant) oxidation# is 1 (on the product) oxidation#is 5 there will be 6 moles of e- on the
