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Nanribet
Answers (1)
l= 1.0, r=0.5/2mm=0.25mm=2.5×10^-4m ,A=πr^2=22/7×(2.5 ×10^-4)^2m^2, R=2 from R=pl/A p= RA/l=2×[22/7)×[2.5×10^-4)^2/1=3.93×10^-7 ohm-meter
