Answers by visitors named: Nano

ΔHv=104,000J/6.02×10^23=1,7276*10^-19 nv/Ns=e^{(-1.7276*10^-19)/[(1.381×10^−23)*(1366)]}=Result Use the result to substitute to: nv/Ns*ρ*Avogadro number/Mw(Cu) = nv/Ns(result from above) * 8.94*( 6.02*10^23/63.546)

watch out that the formula is negative (on e), so it should be in the range of x*10^-4 or 10^-5! And note, that I can not give you the right answer as I succeeded only on my third attempt :) I need help with 11 and 12.