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Let 2^x be A 3^y be B Then A+B=17 ----eq1 And 2^x X 2^2 — 3^y X 3=5 A X 4 — B X 3=5 4A—3B=5 ----eq2 Solve eq1 and eq2 A=8 and B=9 Then 2^x=8 and 3^y=9 2^x=2^3 3^y=3^2 Therefore x=3 and y=2
