Nadir

This page lists questions and answers that were posted by visitors named Nadir.

Questions

The following questions were asked by visitors named Nadir.

Answers

The following answers were posted by visitors named Nadir.

1st you find the vertical component of its speed which = (120)sin(60)=103.92 m/s Gravity's pull will decrease its vertical speed by G (=9.8 m/s^2) Therefore the vertical velocity of the projectile = 103.92 - (9.8)*t (whee t is time in seconds) It will rea...
14 years ago
Current velocity = (time)*(acceleration) + initial velocity 22.5 = time*4 + 0 time = 22.5/4 = 5.625 seconds
14 years ago
Current velocity = (time)*(acceleration) + initial velocity 12 = (0.96)*acceleration + 0 acceleration = 12.5 m/s2
14 years ago
unless there is a special definition of "average rate of change" that im not aware of, ur answer is (f(19) - f(6))/(19-6)
14 years ago
More electrons than protons means the object has a negative charge Since a CL^-1 ion is negative, the two will repel each other
14 years ago
y=2x-2 y+2=2x (y+2)/2 = x y/2 +1 = x Answer: x=y/2+1
14 years ago
work = forcs*distance = 70*1.1 = 77 N.m
14 years ago
divide 4 by 14 on a calc and u get 0.214285714 round to nearest fourth: 0.2143
14 years ago
when u have an even power, the value of y will always be positive, when u have an odd power, the value of y will be negative for x < 0 The higher the power the steeper the slope will be the graphs of x^n for even and odd n's are the same except that they...
14 years ago
If by MB you mean Megabyte (not Megabit) then: 18 MB = 18*8 = 144 Megabits 144/4 = 36 seconds
14 years ago
PEMDAS! do the things in the ( ) first. that'd be b-4 which is probably base minus four then multiply by six.
12 years ago