Answers by visitors named: Nabi

I understand a) but I'm stuck getting started on how take into account the 0.100 times the original volume. Im not sure how to rework the equation. Do I times the E line concentrations by 10? then that will be my new initial and then proceed to find the n...

so for a) I found the x=0.089 and plugged the x in the E line to find the equilibrium concentration. [I3]= 0.098, [I2]= 0.09-0.089= 2 x10^-4. To find the equilibrium ratio do I do [I3] / [I2]? If I do that I got 449 but the answer is 575. Im not sure what...