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Answers (2)
Power,P= I^2R Since power is directly proportional to resistance R, the bulb with greater power will have greater resistance.
GIVEN m=500g=(500/1000)kg=0.5kg h=5.5m Also we know, g=9.8m/s^2 potential energy, PE=m*g*h =0.5*9.8*5.5 =26.95J
